3v^2-37v+12=0

Solution for 3v^2-37v+12=0 equation:

3v^2-37v+12=0

a = 3; b = -37; c = +12;
Δ = b2-4ac
Δ = -372-4·3·12
Δ = 1225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1225}=35$
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-37)-35}{2*3}=\frac{2}{6}
=1/3
$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-37)+35}{2*3}=\frac{72}{6}
=12
$